3x(x-4)=16-7x^2-12x

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Solution for 3x(x-4)=16-7x^2-12x equation: 


Simplifying
3x(x + -4) = 16 + -7x2 + -12x

Reorder the terms:
3x(-4 + x) = 16 + -7x2 + -12x
(-4 * 3x + x * 3x) = 16 + -7x2 + -12x
(-12x + 3x2) = 16 + -7x2 + -12x

Reorder the terms:
-12x + 3x2 = 16 + -12x + -7x2

Add '12x' to each side of the equation.
-12x + 12x + 3x2 = 16 + -12x + 12x + -7x2

Combine like terms: -12x + 12x = 0
0 + 3x2 = 16 + -12x + 12x + -7x2
3x2 = 16 + -12x + 12x + -7x2

Combine like terms: -12x + 12x = 0
3x2 = 16 + 0 + -7x2
3x2 = 16 + -7x2

Solving
3x2 = 16 + -7x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '7x2' to each side of the equation.
3x2 + 7x2 = 16 + -7x2 + 7x2

Combine like terms: 3x2 + 7x2 = 10x2
10x2 = 16 + -7x2 + 7x2

Combine like terms: -7x2 + 7x2 = 0
10x2 = 16 + 0
10x2 = 16

Divide each side by '10'.
x2 = 1.6

Simplifying
x2 = 1.6

Take the square root of each side:
x = {-1.264911064, 1.264911064}

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